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JEE MATHEMATICS MCQ: STATISTICS

1 Easy

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Application +4 | -1

Let the six numbers

a_{1}, a_{2}, a_{3}, a_{4}, a_{5}, a_{6}

be in A.P. and

a_{1}+a_{3}=10

. If the mean of these six numbers is

\frac{19}{2}

and their variance is

\sigma^{2}

, then

8 \sigma^{2}

is equal to:

View answer and explanation

Correct option: D

210

Option D (210) is correct because it involves finding the variance of an arithmetic progression.

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