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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
If f(x)={3x−1,x≥12x+3,x<1,g(x)={3−x,x<22x−3,x≥2f(x)=\left\{\begin{array}{ll}3 x-1, & x \geq 1 \\ 2 x+3, & x < 1\end{array}, g(x)=\left\{\begin{array}{cc}3-x, & x < 2 \\ 2 x-3, & x \geq 2\end{array}\right.\right., then lim⁡x→2f(g(x))=\lim \limits_{{x \rightarrow 2}} f(g(x))=
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Correct option: B
2
Option B (2) is correct because the limit of f(g(x))f(g(x)) as xx approaches 2 is 2, based on the piecewise definitions of f(x)f(x) and g(x)g(x).

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