JEE MATHEMATICS MCQ: LIMITS

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Let

f(x)= \begin{cases}\frac{\sin \left(x^2\right)}{x} & \text { if } x \neq 0 \\ 1 & \text { if } x=0\end{cases}

Then

\lim _{x \rightarrow 0} f(x)

View answer and explanation

Correct option: B

Option B is correct because as x approaches 0, x² also approaches 0, and sin(x²)/x² approaches 1. Therefore, the limit becomes 0 * 1 = 0.

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