If ${S_n} = {1^3} + {2^3} + ... + {n^3}$ and ${T_n} = 1 + 2 + ... + n$, then

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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{S_n} = {1^3} + {2^3} + ... + {n^3}

and

{T_n} = 1 + 2 + ... + n

, then

View answer and explanation

Correct option: C

{S_n} = T_n^2

Option C is correct because the sum of cubes of first n natural numbers is equal to the square of the sum of first n natural numbers.

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