The reaction of ${\rm{C}}{{\rm{H}}_3}{\rm{O}}{{\rm{C}}_2}{{\rm{H}}_5}$ with ${\rm{HI}}$ gives:

${\rm{C}}{{\rm{H}}_3}{\rm{I}} + {{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}$

${\rm{C}}{{\rm{H}}_3}{\rm{I}}$ only

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{OH}}$ only

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{I}} + {\rm{C}}{{\rm{H}}_3}{\rm{OH}}$

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JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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Understanding +4 | -1

The reaction of

\mathrm{C}{\mathrm{H}_3}\mathrm{O}{\mathrm{C}_2}{\mathrm{H}_5}

with

\mathrm{HI}

gives:

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{H}_3}\mathrm{I} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

Option C (

\mathrm{C}{\mathrm{H}_3}\mathrm{I} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

) is correct because the reaction of an ether with HI cleaves the ether bond, with the smaller alkyl group typically forming the iodide and the larger forming the alcohol.

JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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