JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If three numbers be in G.P., then their logarithms will be in

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Correct option: A

A.P.

Option B (

\frac{n}{n+1}

) is correct because the series can be expressed as a telescoping sum, where each term is of the form

\frac{1}{k(k+1)} = \frac{1}{k} - \frac{1}{k+1}

, leading to the result

\frac{n}{n+1}

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}