Question

Consider the following reaction : $2{m{A}}{{m{g}}^ + }{{m{C}}_6}{{m{H}}_{12}}{{m{O}}_6} + {{m{H}}_2}{m{O}} 	o 2{m{Ag}}\left( s ight) + {{m{C}}_6}{{m{H}}_{12}}{{m{O}}_7} + 2{{m{H}}^ + }$ When ammonia is added to the solution, pH is raised to 11. Which half-cell reaction is affected by pH and by how much? ${m{A}}{{m{g}}^ + } + {e^ - } 	o {m{Ag}};E_{{m{red}}}^ \circ = 0.8{m{V}}$ ${{m{C}}_6}{{m{H}}_{12}}{{m{O}}_6} + {{m{H}}_2}{m{O}} 	o {{m{C}}_6}{{m{H}}_{12}}{{m{O}}_7} + 2{{m{H}}^ + } + 2{e^ - };E_{{m{red}}}^ \circ = - 0.05{m{V}}$ ${m{Ag}}\left( {{m{N}}{{m{H}}_3}} ight)_2^ + + {e^ - } 	o {m{Ag}}\left( s ight) + {m{N}}{{m{H}}_3};E_{{m{red}}}^ \circ = 0.337{m{V}}$

Accepted Answer

$E_{{\rm{oxid}}{\rm{.}}}^ \circ $ will increase by a factor of 0.65 from $E_{{\rm{oxid}}{\rm{.}}}^ \circ $

Answer

$E_{{\rm{oxid}}{\rm{.}}}^ \circ $ will decrease by a factor of 0.65 from$E_{{\rm{oxid}}{\rm{.}}}^ \circ $

Answer

$E_{{\rm{red}}{\rm{.}}}^ \circ $ will increase by a factor of 0.65 from $E_{{\rm{red}}{\rm{.}}}^ \circ $

Answer

$E_{{\rm{red}}{\rm{.}}}^ \circ $ will decrease by a factor of 0.65 from$E_{{\rm{red}}{\rm{.}}}^ \circ $

JEE CHEMISTRY MCQ: ELECTRO CHEMISTRY

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