JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

a_{1}, a_{2}, \ldots, a_{n+1}

are in AP, then

\frac{1}{a_{1} a_{2}}+\frac{1}{a_{2} a_{3}}+\cdots+\frac{1}{a_{n} a_{n+1}}

View answer and explanation

Correct option: D

\frac{n}{a_{1} a_{n+1}}

Option D (

\frac{{n}}{{a_{{1}} a_{{n+1}}}}

) is correct because the given series telescopes, simplifying to this expression.

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