JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Easy

1 of 1

Application +4 | -1

A force is represented by

F=a x^2+b t^{\frac{1}{2}}

Where

x=

distance and

t=

time. The dimensions of

b^2 / a

are:

View answer and explanation

Correct option: A

\left[\mathrm{ML}^3 \mathrm{~T}^{-3}\right]

Option A ([

\mathrm{ML}^3 \mathrm{~T}^{-3}

]) is correct because it is derived by finding the dimensions of a and b from the given force equation and then calculating the dimensions of

b^2/a

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