NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Medium

1 of 1

Analyzing +4 | -1

For a common emitter configuration, if

\alpha

and

\beta

have their usual meanings, the incorrect relationship between

\alpha

and

\beta

View answer and explanation

Correct option: A

\frac{1}{\alpha } = \frac{1}{\beta } + 1

Option A (

\frac{1}{\alpha } = \frac{1}{\beta } + 1

) is correct because it is the incorrect relationship between

\alpha

and

\beta

. The correct relationship is

\frac{1}{\alpha } = 1 + \frac{1}{\beta}

More Questions from SEMI CONDUCTOR DEVICES

Practice All Chapter MCQs →

I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}