JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

For

x > 0

, let

f(x)=\int\limits_{1}^x \frac{\log t}{1+\mathrm{t}} \mathrm{dt}

. Then

f(x)+f\left(\frac{1}{x}\right)

is equal to

View answer and explanation

Correct option: C

\frac{1}{2}(\log x)^2

Option C (

\frac{1}{2}(\log x)^2

) is correct because it is the result obtained after simplifying the expression

f(x) + f(\frac{1}{x})

using a suitable substitution and evaluating the resulting integral.

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