$\mathop {\lim }\limits_{x \to - \infty } \left( {3x + \sqrt {9{x^2} - x} } \right)$ equals

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to - \infty } \left( {3x + \sqrt {9{x^2} - x} } \right)

equals

View answer and explanation

Correct option: B

\frac{1}{6}

Option B (

\frac{1}{6}

) is correct because after rationalizing and simplifying, the limit evaluates to 1/6 as x approaches negative infinity.

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