If $400\,\,{\rm{\Omega }}$ of resistance is made by adding four $100\,\,{\rm{\Omega }}$ resistance of tolerance ${\rm{5}}\,\,{\rm{\% }}$, then the tolerance of the combination is

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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400\,\,\mathrm{\Omega }

of resistance is made by adding four

100\,\,\mathrm{\Omega }

resistance of tolerance

\mathrm{5}\,\,\mathrm{\% }

, then the tolerance of the combination is

View answer and explanation

Correct option: B

\mathrm{5}\,\,\mathrm{\% }

Option B (

\mathrm{5}\,\mathrm{\% }

) is correct because the tolerance of the combination remains the same as the individual resistors in a series combination.

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\mathrm{\rho }

3\,\,{\mathrm{m}^3}

3\,\,\mathrm{\Omega }

4.7\,\, \times \,\,{10^6}\,\,\mathrm{\Omega }\,\, \pm \,\,5\,\,\%

22.5\,cm