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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
For each x∈Rx \in \mathbf{R}, let [x][x] be greatest integer less than or equal to xx. Then lim⁡x→0x([x]+∣x∣)sin⁡[x]x\lim _{x \rightarrow 0} \frac{x([x]+|x|) \sin [x]}{x} is equal to
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Correct option: A
−sin⁡1-\sin 1
Option A (−sin⁡1-\sin 1) is correct because after evaluating the left-hand limit, the result is −sin⁡1-\sin 1.

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