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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1
The number of bijective functions f:{1,3,5,7,…f:\{1,3,5,7, \ldots, 99}→{2,4,6,8,……,100}99\} \rightarrow\{2,4,6,8, \ldots \ldots, 100\} such that f(3)≥f(9)≥f(15)≥f(21)≥…≥f(99)f(3) \geq f(9) \geq f(15) \geq f(21) \geq \ldots \geq f(99), is _____.
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Correct option: B
50P33{ }^{50} P_{33}
Option B (50P33{ }^{50} P_{33}) is correct because we choose 17 elements out of 50 for the decreasing sequence and arrange the remaining 33 elements.

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