When the temperature of a rod increases from $t$ to $t + \Delta t$ its moment of inertia increases from $I$ to $I + \Delta I$. If $\alpha $ be the coefficient of linear expansion of the rod, then the value of $\frac{{\Delta I}}{I}$ is

NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

When the temperature of a rod increases from

t

t + \Delta t

its moment of inertia increases from

I

I + \Delta I

. If

\alpha

be the coefficient of linear expansion of the rod, then the value of

\frac{{\Delta I}}{I}

View answer and explanation

Correct option: A

2\alpha \Delta t

Option A (

2\alpha \Delta t

) is correct because it is the relationship between the change in moment of inertia and the coefficient of linear expansion.

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