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JEE PHYSICS MCQ: WAVES

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Analyzing +4 | -1
A travelling wave y=Asin⁡(kx−ωt+θ)y=A \sin (k x-\omega t+\theta) passes from a heavier string to a lighter string. The reflected wave has amplitude 0.5 A0.5 \mathrm{~A}. The junction of the strings is at x=0x=0. The equation of the reflected wave is:
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Correct option: D
y′=−0.5Asin⁡(kx+ωt−θ)y^{\prime}=-0.5 A \sin (k x+\omega t-\theta)
Option D (y′=−0.5Asin⁡(kx+ωt−θ)y^{\prime}=-0.5 A \sin (k x+\omega t-\theta)) is correct because the wave is reflected from a rarer medium, so there is no phase change, and the direction of propagation is reversed.

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