If ${{\rm{\vec A}}_1}\,and\,{{\rm{\vec A}}_2}$ are two non-collinear unit vectors and if $\left| {{{{\rm{\vec A}}}_1} + {{{\rm{\vec A}}}_2}} \right| = \sqrt 3 $, then the value of $\left( {{{{\rm{\vec A}}}_1} - {{{\rm{\vec A}}}_2}} \right).\left( {2{{{\rm{\vec A}}}_1} + {{{\rm{\vec A}}}_2}} \right)$

NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Medium

1 of 1

Application +4 | -1

{\mathrm{\vec A}_1}\,and\,{\mathrm{\vec A}_2}

are two non-collinear unit vectors and if

\left| {{{\mathrm{\vec A}}_1} + {{\mathrm{\vec A}}_2}} \right| = \sqrt 3

, then the value of

\left( {{{\mathrm{\vec A}}_1} - {{\mathrm{\vec A}}_2}} \right).\left( {2{{\mathrm{\vec A}}_1} + {{\mathrm{\vec A}}_2}} \right)

View answer and explanation

Correct option: B

\frac{1}{2}

Option B (

\frac{1}{2}

) is correct because it is the result of the dot product after simplification using the given condition.

Practice All Chapter MCQs →

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)