JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The efficiency of a Carnot engine is

60 \%

. If the temperature of source is

127^{\circ} \mathrm{C}

. The sink must be maintained at

View answer and explanation

Correct option: C

-113^{\circ} \mathrm{C}

The correct answer is C (

-113^{\circ} \mathrm{C}

) because it is the correct sink temperature calculated using the Carnot efficiency formula.

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