JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

Suppose that the electric field part of an electromagnetic wave in vacuum is

\vec{E}=(3.1 \mathrm{~N} / \mathrm{C}) \cos \left[(1.8 \mathrm{~rad} / \mathrm{m}) y+\left(5.4 \times 10^8 \mathrm{~rad} / \mathrm{s}\right) {t}\right] \hat{i}

. What is the frequency

{v}

View answer and explanation

Correct option: A

86 \mathrm{~MHz}

Option A (86 MHz) is correct because the frequency is calculated from the angular frequency using the formula

v = \frac{\omega}{{2\pi}}

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