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NEET UG PHYSICS MCQ: WAVE OPTICS

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Analyzing +4 | -1
In a young's double slit experiment light of wavelength 600 nm600 \mathrm{~nm} is used. P\mathrm{P} is the nearest point from the central maximum where intensity is 3/4th 3 / 4^{\text {th }} of the maximum intensity. What percentage of the maximum intensity is observed at point PP if light is replaced by the wavelength 400 nm400 \mathrm{~nm} ?
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Correct option: B
75%75 \%
Option B (75%) is correct because when the wavelength changes, the phase difference at point P changes, leading to a different intensity which is calculated to be 75% of the maximum intensity.

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