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JEE MATHEMATICS MCQ: STATISTICS

1 Easy
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Application +4 | -1
If βˆ‘i=19(xiβˆ’5)=9\sum\limits_{i = 1}^9 {\left( {{x_i} - 5} \right) = 9\mathrm{ }} and βˆ‘i=19(xiβˆ’5)2=45\sum\limits_{i = 1}^9 {{{\left( {{x_i} - 5} \right)}^2} = 45}, then the standard deviation of the 9 items then the standard deviation of the 9 items x1,x2,...,x9{x_1},{x_2},...,{x_9} is
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Correct option: C
2
Option C (2) is correct because the standard deviation is calculated using the given sums and remains unchanged when observations are shifted by a constant.

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