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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
On the ellipse x24+y29=1\frac{x^2}{4}+\frac{y^2}{9}=1, one of the points of which the normals are parallel to the line 2x−y=12 x-y=1, is
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Correct option: C
(210,910)\left(\frac{2}{\sqrt{10}}, \frac{9}{\sqrt{10}}\right)
Option C ((210,910)\left(\frac{2}{\sqrt{10}}, \frac{9}{\sqrt{10}}\right)) is correct because it represents a point on the ellipse where the normal's slope matches that of the given line.

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