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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The nnth term of the sequence 212,1713,119,2023…2 \frac{1}{2}, 1 \frac{7}{13}, 1 \frac{1}{9}, \frac{20}{23} \ldots is
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Correct option: C
205n+3\frac{20}{5 n+3}
Option C is correct because the nth term of the sequence can be found by taking the reciprocal of the terms, recognizing an A.P., and then finding the reciprocal of the nth term of that A.P.

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