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JEE CHEMISTRY MCQ: SURFACE CHEMISTRY

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Plot of log⁡xm\log \frac{x}{m} against log⁡p\log p is a straight line inclined at an angle of 45∘45^\circ. When the pressure is 0.5 atm and Freundlich parameter, kk is 10, the amount of solute adsorbed per gram of adsorbent will be (log 5=0.6990)
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Correct option: D
5  g5\mathrm{ }\;g
Option D (5 g) is correct because it is the amount of solute adsorbed per gram of adsorbent calculated using the Freundlich adsorption isotherm equation with the given parameters.

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