JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

2 \cos x < \sqrt{3}

and

x \in[-\pi, \pi]

, then the solution set for

x

View answer and explanation

Correct option: A

\left[-\pi,-\frac{\pi}{6}\right) \cup\left(\frac{\pi}{6}, \pi\right]

Option A ([-π,-

\frac{π}{6}

) ∪ (

\frac{π}{6}

, π]) is correct because it represents the interval where

\cos x < \frac{{\sqrt{{3}}}}{{2}}

within the given range of

x \in [-\pi, \pi]

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