JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Hard

1 of 1

Application +4 | -1

The sum of first

n

terms of the series

\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\frac{3}{1+3^2+3^4}+\ldots

View answer and explanation

Correct option: B

\frac{n(n+1)}{2\left(n^2+n+1\right)}

Option B (

\frac{{n(n+1)}}{{2(n^2+n+1)}}

) is correct because it represents the sum of the first n terms of the given series.

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