JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

f

and

g

are differentiable function in

[0,1]

satisfying

f(0)=2=g(1), g(0)=0

and

f(1)=6

, then for some

c \in(0,1):

View answer and explanation

Correct option: B

f^{\prime}(c)=2 g^{\prime}(c)

Option B (

f^{\prime}(c)=2 g^{\prime}(c)

) is correct because it follows from applying Rolle's theorem to the function

h(x) = f(x) - 2g(x)

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x

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[x]

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x=k, k

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\frac{{dy}}{{dx}}

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