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JEE PHYSICS MCQ: WAVE OPTICS

1 Medium
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Application +4 | -1
In YDSE, the distance from central position where the intensity fall to half of maxima.
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Correct option: B
λD4d\frac{{\lambda D}}{{4d}}
Option B (λD4d\frac{{\lambda D}}{{4d}}) is correct because it is the distance from the central position where the intensity falls to half of the maximum intensity in YDSE.

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