JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

Let

a_n

be the nth term an A.P. If

\sum\limits_{r=1}^{100} a_{2 r}=\alpha

and

\sum\limits_{r=1}^{100} a_{2 r-1}=\beta

, then the common difference of the A.P., is

View answer and explanation

Correct option: A

\frac{\alpha-\beta}{100}

Option A (

\frac{\alpha-\beta}{100}

) is correct because it determines the common difference of the A.P. based on the given sums of even and odd terms.

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