The equation of the normal to the curve $y=\sin x$ at $(0,0)$, is

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The equation of the normal to the curve

y=\sin x

(0,0)

, is

View answer and explanation

Correct option: C

x+y=0

Option C (

x+y=0

) is correct because the slope of the normal at (0,0) is -1, and the line passes through the origin.

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z