JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Hard

1 of 1

Analyzing +4 | -1

For

x \in R, x \neq-1

, if

(1+x)^{2016}+x(1+x)^{2015}+x^{2}

(1+x)^{2014}+\ldots .+\mathrm{x}^{2016}=\sum_{\mathrm{i}=0}^{2016} \mathrm{a}_{\mathrm{i}} \mathrm{x}^{\mathrm{i}}

, then

\mathrm{a}_{17}

is equal to

:

View answer and explanation

Correct option: A

\frac{2017 !}{17 ! 2000 !}

Option A (

\frac{{2017 !}}{{17 ! 2000 !}}

) is correct because by simplifying the given expression, we can find the coefficient of x¹⁷.

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