JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A constant torque is acting on a wheel. If starting from rest, the wheel makes

n

rotations in

t

second, the angular acceleration

\alpha=

View answer and explanation

Correct option: A

\frac{4 \pi n}{t^2} \mathrm{~rad} \mathrm{~s}^{-2}

Option A (

\frac{4 \pi n}{t^2} \mathrm{~rad} \mathrm{~s}^{-2}

) is correct because it is derived from the rotational kinematic equation

\theta = \omega_0 t + \frac{1}{2} \alpha t^2

, where

\theta = 2 \pi n

and

\omega_0 = 0

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