JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to 0} \frac{{{{\left( {1 + x} \right)}^8} - 1}}{{{{\left( {1 + x} \right)}^2} - 1}}

is equal to

View answer and explanation

Correct option: C

Option C (4) is correct because after factoring and simplifying the expression, the limit as x approaches 0 is 4.

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\lim \limits_{{x \rightarrow 0}}\left(\frac{1}{x^2}-\operatorname{cosec}^2 x\right)

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