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NEET UG PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Application +4 | -1

The threshold frequency of a metal with work function

6.63 \mathrm{~eV}

is:

View answer and explanation

Correct option: A

1.6 \times 10^{15} \mathrm{~Hz}

Option A (

1.6 \times 10^{15} \mathrm{~Hz}

) is correct because it is calculated using the formula

f = \phi/h

, where

\phi

is the work function and

h

is Planck's constant.

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If the Broglie wavelengths associated with a proton and an

\alpha

- particle are equal, then the ratio of velocities of the proton and the

\alpha

- particle will be: If the wavelength of incident light changes from 400 nm to 300 nm, the stopping potential for photoelectrons emitted from a surface becomes approximately In photo-electric effect, when graph is plotted for stopping potential versus frequency of incident light, for different metals, then: The radiation corresponding to

3 \to 2

transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of

3 \times {10^{ - 4}}\,T.

If the radius of the largest circular path followed by these electrons is 10.0 mm, the work function of the metal is close to The shortest wavelength of

X

-rays emitted from an

X

-ray tube depends on the Planck’s constant has the dimensions of