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NEET UG CHEMISTRY MCQ: SOLID STATE
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Medium
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Analyzing
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A substance AB crystallizes in cubic
closest packing (C.C.P.) with B occupying
half the tetrahedral voids. One litre of
the crystal is doped with 1 mole atoms of
C some of which replace the B atoms
and remaining occupy few interstitial
voids without affecting the dimensions of
cubic crystal lattice. If density of crystal
before doping is 4.8 gm/millilitre and
density after doping is 4.795 gm /ml then
calculate % of C added with replace B
atoms.
(Given : Atomic weight : A, B
and C : 40, 30, 15)
closest packing (C.C.P.) with B occupying
half the tetrahedral voids. One litre of
the crystal is doped with 1 mole atoms of
C some of which replace the B atoms
and remaining occupy few interstitial
voids without affecting the dimensions of
cubic crystal lattice. If density of crystal
before doping is 4.8 gm/millilitre and
density after doping is 4.795 gm /ml then
calculate % of C added with replace B
atoms.
(Given : Atomic weight : A, B
and C : 40, 30, 15)
View answer and explanation
Correct option: B
66.67
Option B (66.67) is correct because it is the percentage of C atoms that replace B atoms calculated based on the change in density after doping.
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