JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Hard

1 of 1

Application +4 | -1

The deceleration experienced by a moving motorboat after its engine is cut off, is given by

\mathrm{dv} / \mathrm{dt}=-\mathrm{kv}^3

where

\mathrm{k}

is constant. If

\mathrm{v}_0

is the magnitude of the velocity at cut-off, the magnitude of the velocity at a time

t

after the cut-off is

View answer and explanation

Correct option: A

\frac{\mathrm{v}_0}{\sqrt{\left(2 \mathrm{v}_0{ }^2 \mathrm{kt}+1\right)}}

Option A (

\frac{{\mathrm{v}_0}}{{\sqrt{{\left(2 \mathrm{v}_0{ }^2 \mathrm{kt}+1\right)}}}}

) is correct because it is derived by solving the given differential equation with the initial condition.

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\mathrm{g}

\mathrm{h}

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t

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120 \mathrm{~m}

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\mathrm{m}

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