JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} {{\text{In}}\left( {\left\{ x \right\}} \right)}&;&{x \notin I} \\ 0&;&{x \in I} \end{array}} \right.

; (where {x} is fractional part function), then the area enclosed by curves

y = f\left( x \right),y = f\left( {\left| x \right|} \right),x \in \left[ { - 5,0} \right]

and

y = 0

, is

View answer and explanation

Correct option: A

5\,{\text{In}}\left( {\frac{e}{2}} \right)

Option D (3) is correct because the equation f(x) - g(x) = 0 has 3 real solutions based on the intersection of the graphs.

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