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JEE PHYSICS MCQ: RAY OPTICS

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An optical fibre (μ=1.72)(\mu=1.72) is surrounded by a glass coating (μ=1.50)(\mu=1.50). Find the critical angle for total internal reflection at the fibre-glass interface.
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Correct option: B
sin⁡−1(7526)\sin ^{-1}\left(\frac{75}{26}\right)
Option A (sin⁡−1(7586)\sin ^{-1}\left(\frac{75}{86}\right)) is correct because it is the critical angle calculated using Snell's law at the interface between the optical fiber and the glass coating.

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