JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Hard

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Application +4 | -1

The sum of

1 \cdot n+2 \cdot(n-1)+3 \cdot(n-2)+\ldots n \cdot(1) \, \forall \, n \in \mathrm{N}

View answer and explanation

Correct option: C

\frac{n(n+1)(n+2)}{6}

Option C (

\frac{{n(n+1)(n+2)}}{{6}}

) is correct because it represents the sum of the series after simplification of the rth term and summation.

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