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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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Application +4 | -1
A uniform electric field of 100 N/C100 \mathrm{~N} / \mathrm{C} exists in XY\mathrm{XY} plane making an angle 60∘60^{\circ} with +x+\mathrm{x} direction. Consider points A(1,2,3)mA(1,2,3) \mathrm{m} and B(3,2,1)mB(3,2,1) \mathrm{m} then VA−VB\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}} is:
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Correct option: A
100 volt
Option A (100 volt) is correct because the potential difference is calculated using the formula VA−VB=E‾⋅(r‾B−r‾A)V_A - V_B = \overline{E} \cdot (\overline{r}_B - \overline{r}_A).

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