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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If sum of xx terms of a series is Sx=1(2x+3)(2x+1)S_x=\frac{1}{(2 x+3)(2 x+1)} whose rth r^{\text {th }} term is TrT_r. Then, ∑r=1n1Tr\sum\limits_{{r=1}}^n \frac{1}{T_r} is equal to
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Correct option: B
−14∑(2r+1)(2r−1)(2r+3)-\frac{1}{4} \sum(2 r+1)(2 r-1)(2 r+3)
Option B is correct because by finding the rth term of the series and then taking the reciprocal, the summation can be expressed as the negative of 1/4 times the sum of the product of the given terms.

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