Skip to main content
Back to NUCLEI

JEE PHYSICS MCQ: NUCLEI

1 Medium
1 of 1
Application +4 | -1
In the given reaction, find value of QQ value.

6C13⟶6C12+0n1+(Q−value){ }_6 C^{13} \longrightarrow {}_6C^{12}+{ }_0 n^1+(Q-\text {value})

Given: mass of 6C13⇒x{ }_6 C^{13} \Rightarrow x

mass of 6C12⇒y{ }_6 C^{12} \Rightarrow y

mass of 0n1⇒z{ }_0 n^1 \Rightarrow z
View answer and explanation
Correct option: B
(y+z−x)C2(y+z-x) C^2
Option B ((y+z−x)C2(y+z-x) C^2) is correct because the Q-value is calculated as the mass defect multiplied by C2C^2.

More Questions from NUCLEI

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.