JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

\alpha+i \beta=\tan ^{-1} z, z=x+i y

and

\alpha

is constant, then the locus of

z

View answer and explanation

Correct option: A

x^2+y^2+2 x \cot 2 \alpha=1

Option A (

x^2+y^2+2 x \cot 2 \alpha=1

) is correct because it is derived by taking the tangent of both sides, separating real and imaginary parts, and manipulating the equation.

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