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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Surface density of charge on a charged conducting sphere of radius '

R

' in terms of electric intensity '

E

' at a distance '

r

' in free space is

\left(r>R, \varepsilon_0= \text{Permittivity of free space}\right)

View answer and explanation

Correct option: C

\varepsilon_0 E\left(\frac{r}{R}\right)^2

Option C (

\varepsilon_0 E\left(\frac{r}{R}\right)^2

) is correct because it correctly relates the surface charge density to the electric field at a distance r from the sphere.

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