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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
sin⁡x⋅sin⁡(60∘−x)⋅sin⁡(60∘+x)=1/8\sin x \cdot \sin \left(60^{\circ}-x\right) \cdot \sin \left(60^{\circ}+x\right)=1 / 8 and n∈Zn \in \mathbb{Z}, then:
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Correct option: B
x=nπ3+(−1)nπ18x=\frac{n \pi}{3}+(-1)^n \frac{\pi}{18}
Option B (x=nπ3+(−1)nπ18x=\frac{{n \pi}}{{3}}+(-1)^n \frac{{\pi}}{{18}}) is correct because it is derived by using the trigonometric identity and solving the resulting sine equation.

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