An object moving at a speed of ${\rm{5}}\,\,{\rm{m}}\,{\rm{/}}\,{\rm{s}}$ towards a concave mirror of focal length $f = 1\,\,{\rm{m}}$ is at a distance of ${\rm{9}}\,\,{\rm{m}}$. The average speed of the image is

$\frac{1}{5}\,\,{\rm{m}}\,\,/\,\,{\rm{s}}$

$\frac{1}{10}\,\,{\rm{m}}\,\,/\,\,{\rm{s}}$

$\frac{5}{9}\,\,{\rm{m}}\,\,/\,\,{\rm{s}}$

$\frac{4}{{10}}\,\,{\rm{m}}/{\rm{s}}$

NEET UG PHYSICS MCQ: RAY OPTICS

1 Hard

1 of 1

Application +4 | -1

An object moving at a speed of

\mathrm{5}\,\,\mathrm{m}\,\mathrm{/}\,\mathrm{s}

towards a concave mirror of focal length

f = 1\,\,\mathrm{m}

is at a distance of

\mathrm{9}\,\,\mathrm{m}

. The average speed of the image is

View answer and explanation

Correct option: A

\frac{1}{5}\,\,\mathrm{m}\,\,/\,\,\mathrm{s}

Option A (

\frac{1}{5}\mathrm{\\ m}\mathrm{\\ }/\mathrm{\\ }\mathrm{\\ s}

) is correct because it is derived from differentiating the mirror formula and substituting the given values.

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