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NEET UG PHYSICS MCQ: GRAVITATION

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A body revolved around the sun 27 times faster than the earth. What is the ratio of their radii

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Correct option: B

\frac{1}{9}

Option B (

\frac{1}{9}

) is correct because, using Kepler's third law (

T^2 \propto R^3

), if the body revolves 27 times faster, its time period is 1/27 of Earth's, leading to a radius ratio of (1/27)^(2/3) = 1/9.

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.