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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If f(z)=z4−8z3+4z2+4z+39f(z)=z^4-8 z^3+4 z^2+4 z+39 and f(3+2i)=a+ibf(3+2 i)=a+i b, then a:b=a: b=
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Correct option: B
−1:8-1: 8
Option B (-1: 8) is correct because by dividing f(z)f(z) by z2−6z+13z^2-6z+13 and substituting z=3+2iz=3+2i, we find the ratio a:b is -1:8.

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