JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\frac{d}{d x} G(x)=\frac{e^{\tan x}}{x}, x \in(0, \pi / 2)

, then

\int\limits_{{1 / 4}}^{1 / 2} \frac{2}{x} \cdot e^{\tan \left(\pi x^2\right)} d x

is equal to

View answer and explanation

Correct option: A

G(\pi / 4)-G(\pi / 16)

Option A (

G(\pi / 4)-G(\pi / 16)

) is correct because after substituting and changing variables, the integral can be expressed in terms of G(x) and evaluated at the limits.

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